# Write a Program to Find Minimum Suffix Flips

# 1529. Minimum Suffix Flips

You are given a 0-indexed binary string target of length n. You have another binary string s of length n that is initially set to all zeros. You want to make s equal to target.

In one operation, you can pick an index i where 0 <= i < n and flip all bits in the inclusive range [i, n - 1]. Flip means changing '0' to '1' and '1' to '0'.Return the minimum number of operations needed to make s equal to target.

```### Example 1:
“`
Input: target = “10111”
Output: 3
Explanation: Initially, s = “00000”.
Choose index i = 2: “00000” -> “00111”
Choose index i = 0: “00111” -> “11000”
Choose index i = 1: “11000” -> “10111”
We need at least 3 flip operations to form target.
“`
```
```### Example 2:
```
Input: target = "101"
Output: 3
Explanation: Initially, s = "000".
Choose index i = 0: "000" -> "111"
Choose index i = 1: "111" -> "100"
Choose index i = 2: "100" -> "101"
We need at least 3 flip operations to form target.
```
```
```Constraints:
```
n == target.length
1 <= n <= 105
target[i] is either '0' or '1'.
```
```
```/**
* @param {string} target
* @return {number}
*/
var minFlips = function(target) {
let flips = 0;
target = target.replace(/^0+/, '');
for (let i = 0; i < target.length; i++) {
if (target[i] !== target[i+1]) {
flips++;
}
}
return flips;
};
```