# Check If a String Can Break Another String

# 1433. Check If a String Can Break Another String

Given two strings: s1 and s2 with the same size, check if some permutation of string s1 can break some permutation of string s2 or vice-versa. In other words s2 can break s1 or vice-versa.

A string x can break string y (both of size n) if x[i] >= y[i] (in alphabetical order) for all i between 0 and n-1.

```### Example 1:
```
Input: s1 = "abc", s2 = "xya"
Output: true
Explanation: "ayx" is a permutation of s2="xya" which can break to string "abc" which is a permutation of s1="abc".
```
```
```### Example 2:
```
Input: s1 = "abe", s2 = "acd"
Output: false
Explanation: All permutations for s1="abe" are: "abe", "aeb", "bae", "bea", "eab" and "eba" and all permutation for s2="acd" are: "acd", "adc", "cad", "cda", "dac" and "dca". However, there is not any permutation from s1 which can break some permutation from s2 and vice-versa.
```
```
```Constraints:
```
s1.length == n
s2.length == n
1 <= n <= 10^5
All strings consist of lowercase English letters.
```
```
```/**
* @param {string} s1
* @param {string} s2
* @return {boolean}
*/
const checkIfCanBreak = function(s1, s2) {
const str1 = s1.split('').sort().join('');
const str2 = s2.split('').sort().join('');

const isBreakable = (a, b) => {
for(let i = 0; i < a.length; i++) {
if (b[i] < a[i]) {
return false;
}
}
return true;
}

return isBreakable(str1, str2) || isBreakable(str2, str1);
};
```